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} o } P ÁH r P N J p X D D ¡p¢V £h¢V V j ¤May 10, 11ij=jk=ki=0 Today I will discuss about the cross product of unit vectors i x j = k j x k=i k x i =j j x i= k k x j= i i x k= j and i x i = j xj = k x k =0 Do you know how the above results come?
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Dec 15, 08I, J, K defines a vector to a point or a plane If I recall correctly (I'm a long time ago CNC, robot and CMM programmer) IJK are developed from the sine of the angle relative to the plane being used by the XYZ point ie X0 Y0 Z0 I0 J0 K1 would be looking straight down on the plane along the Z axis at the point at 0,0,0V , } Z l P v } oI j h k v Z h j Z s Z l v k y i h Z ^ j _ k m Publications du BIT, Bureau international du Travail, CH1211 G _nève 22, Suisse I h w l h f m ` _ Z ^ j _ k m f h ` g h _ k i e Z l g h i h e m q b l v d Z l Z e h b e b k i b k h d g h \ u o i m e b d Z p b c G Z i _ q Z l Z g h \ R \ _ c p Z j b b L
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